{"id":17051,"date":"2024-04-13T12:11:13","date_gmt":"2024-04-13T12:11:13","guid":{"rendered":"http:\/\/dudoanlosongthu.com\/?p=17051"},"modified":"2024-04-13T12:11:13","modified_gmt":"2024-04-13T12:11:13","slug":"du-doan-lo-bach-thu-phat-tai-trung-lon","status":"publish","type":"post","link":"https:\/\/dudoanlode3mien.cfd\/du-doan-lo-bach-thu-phat-tai-trung-lon\/","title":{"rendered":"D\u1ef1 \u0111o\u00e1n l\u00f4 B\u1ea1ch th\u1ee7 ph\u00e1t t\u00e0i tr\u00fang l\u1edbn"},"content":{"rendered":"

B\u1ea1ch th\u1ee7 l\u00f4 l\u00e0 c\u00e1ch ch\u01a1i \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi s\u1eed d\u1ee5ng b\u1edfi khi tr\u00fang B\u1ea1ch th\u1ee7 th\u00ec th\u01b0\u1eddng \u0103n r\u1ea5t l\u1edbn. Tuy nhi\u00ean t\u1ec9 l\u1ec7 v\u1ec1 l\u00f4 B\u1ea1ch th\u1ee7 l\u00e0 kh\u00e1 th\u1ea5p. V\u1eady l\u00e0m th\u1ebf n\u00e0o \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n l\u00f4 B\u1ea1ch th\u1ee7<\/strong> ph\u00e1t t\u00e0i tr\u00fang l\u1edbn. B\u00e0i vi\u1ebft n\u00e0y ch\u00fang t\u00f4i xin g\u1eedi t\u1edbi anh em g\u1ea7n xa c\u00e1c b\u00ed k\u00edp gi\u00fap soi c\u1ea7u ch\u00ednh x\u00e1c.<\/p>\n

Ph\u01b0\u01a1ng ph\u00e1p d\u1ef1 \u0111o\u00e1n l\u00f4 B\u1ea1ch th\u1ee7<\/h2>\n

L\u00f4 B\u1ea1ch th\u1ee7 l\u00e0 h\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 kh\u00e1 ph\u1ed5 bi\u1ebfn hi\u1ec7n nay. Th\u1ef1c ch\u1ea5t \u0111\u00f3 l\u00e0 c\u00e1ch ch\u01a1i ch\u1ec9 \u0111\u00e1nh duy nh\u1ea5t 1 con, kh\u00f4ng \u0111\u00e1nh d\u00e0n tr\u1ea3i m\u00e0 l\u00e0 \u0111\u00e1nh t\u1eadp trung. \u01afu \u0111i\u1ec3m c\u1ee7a c\u00e1c ch\u01a1i n\u00e0y s\u1ebd mang \u0111\u1ebfn chi\u1ebfn th\u1eafng l\u00e0 l\u1ee3i nhu\u1eadn kh\u00f4ng ng\u1edd, l\u00e0 c\u01a1 h\u1ed9i \u0111\u1ed5i \u0111\u1eddi c\u1ee7a nhi\u1ec1u ng\u01b0\u1eddi.
\n\u0110\u1ec3 d\u1ef1 \u0111o\u00e1n l\u00f4 B\u1ea1ch th\u1ee7 ch\u00ednh x\u00e1c<\/strong>, ch\u00fang t\u00f4i xin gi\u1edbi thi\u1ec7u t\u1edbi anh em c\u00e1ch t\u00ednh theo x\u00e1c su\u1ea5t tr\u00fang v\u00e0 tr\u01b0\u1ee3t c\u1ee7a c\u00e1c c\u1eb7p s\u1ed1.<\/p>\n

\"du-doan-lo-bach-thu-8\"
D\u1ef1 \u0111o\u00e1n l\u00f4 B\u1ea1ch th\u1ee7 ph\u00e1t t\u00e0i tr\u00fang l\u1edbn<\/figcaption><\/figure>\n

C\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t tr\u00fang B\u1ea1ch th\u1ee7 l\u00f4<\/a><\/h3>\n

C\u00f3 27 gi\u1ea3i l\u00f4 tr\u00ean t\u1ed5ng s\u1ed1 100 k\u1ebft qu\u1ea3, nh\u01b0 v\u1eady x\u00e1c su\u1ea5t tr\u00fang kh\u00e1 cao. Nhi\u1ec7m v\u1ee5 \u0111\u1ec3 \u0111\u00e1nh tr\u00fang B\u1ea1ch th\u1ee7 l\u00e0 c\u00e1ch m\u00e0 b\u1ea1n l\u1ef1a ch\u1ecdn duy nh\u1ea5t 1 c\u1eb7p s\u1ed1 \u0111\u1ec3 ch\u01a1i. \u0110o\u00e1n tr\u00fang b\u1ea1n s\u1ebd l\u00e0 ng\u01b0\u1eddi chi\u1ebfn th\u1eafng.
\nNh\u01b0 v\u1eady c\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t tr\u00fang B\u1ea1ch th\u1ee7 l\u00f4 s\u1ebd l\u00e0:
\n1 \u2013 0,99^27 = 23,7657%. (trong \u0111\u00f3 0,99^27 l\u00e0 x\u00e1c su\u1ea5t tr\u01b0\u1ee3t c\u1ea3 27 con)<\/p>\n

 <\/p>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang Song th\u1ee7 l\u00f4<\/a><\/h3>\n

\u0110i\u1ec1u ki\u1ec7n \u0111\u1ec3 tr\u00fang Song th\u1ee7 l\u00f4 l\u00e0 d\u1ef1 \u0111o\u00e1n \u0111\u00fang c\u1ea3 2 con s\u1ed1. C\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u00f2n l\u1ea1i \u0111\u1ec1u t\u00ednh l\u00e0 tr\u01b0\u1ee3t l\u00f4. C\u1ee5 th\u1ec3: tr\u01b0\u1eddng h\u1ee3p ch\u1ec9 tr\u00fang 1 trong 2 con v\u00e0 tr\u01b0\u1eddng h\u1ee3p tr\u01b0\u1ee3t c\u1ea3 2 con \u0111\u1ec1u l\u00e0 tr\u01b0\u1ee3t l\u00f4 Song th\u1ee7.
\nCT t\u00ednh x\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 hai con = 0,98^27 = 57,957%.
\nCT t\u00ednh x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 trong 2 con: 2 * x\u00e1c su\u1ea5t tr\u00fang 1 l\u00f4 * x\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4
\nThay s\u1ed1 v\u00e0o ta \u0111\u01b0\u1ee3c: 2 * 23,7657% * 0,99^27 = 36,238%.
\nC\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang Song th\u1ee7 l\u00f4: X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 2 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con.
\nThay s\u1ed1: 57,957% + 36,238% = 94,195%.
\nT\u1eeb \u0111\u00f3 suy ra c\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t tr\u00fang Song th\u1ee7 l\u00f4 100% \u2013 X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang
\nThay s\u1ed1 ta \u0111\u01b0\u1ee3c: 00 \u2013 94,195% = 5,8%<\/p>\n

Ct \u0111\u1ec3 t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/a><\/h3>\n

T\u01b0\u01a1ng t\u1ef1 nh\u01b0 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 Song th\u1ee7. Nh\u01b0ng \u0111\u1ed1i v\u1edbi tr\u01b0\u1eddng h\u1ee3p l\u00f4 xi\u00ean 3 th\u00ec h\u01a1i ph\u1ee9c t\u1ea1p h\u01a1n.
\n\u0110\u1ec3 tr\u00fang l\u00f4 xi\u00ean ba \u0111i\u1ec1u ki\u1ec7n b\u1eaft bu\u1ed9c b\u1ea1n ph\u1ea3i d\u1ef1 \u0111o\u00e1n \u0111\u00fang c\u1ea3 3 con s\u1ed1. T\u1ea5t c\u1ea3 c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u00f2n l\u1ea1i \u0111\u1ec1u to\u1ea1ch l\u00f4. C\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u01b0\u1ee3t l\u00f4 xi\u00ean 3:
\n-TH1: Ch\u1ec9 d\u1ef1 \u0111o\u00e1n \u0111\u00fang 1 trong 3 s\u1ed1
\n-TH2: D\u1ef1 \u0111o\u00e1n \u0111\u00fang 2 trong 3 con s\u1ed1
\n-TH3: Kh\u00f4ng d\u1ef1 \u0111o\u00e1n \u0111\u00fang b\u1ea5t c\u1ee9 s\u1ed1 n\u00e0o
\nSuy ra c\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3 l\u00e0:
\nX\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3 = X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 3 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 2 con
\nThay s\u1ed1: 0,97^27 + 3 * 23,7675% * 0,98^27 + 3 * 5,8% * 0,99^27 = 98,527%
\nV\u1eady, x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3 = 100% \u2013 98,527% = 1,473%.<\/p>\n

K\u1ebft lu\u1eadn<\/h2>\n

C\u00e1ch d\u1ef1 \u0111o\u00e1n l\u00f4 B\u1ea1ch th\u1ee7<\/strong> tr\u1edf l\u00ean \u0111\u01a1n gi\u1ea3n h\u01a1n khi b\u1ea1n c\u00f3 trong tay c\u00e1c c\u00f4ng th\u1ee9c t\u00ednh b\u00ean tr\u00ean. L\u01b0u \u00fd, kh\u00f4ng c\u00f3 c\u00f4ng th\u1ee9c n\u00e0o l\u00e0 ch\u00ednh x\u00e1c 100%, b\u1ea1n n\u00ean \u00e1p d\u1ee5ng th\u00eam c\u00e1c ph\u01b0\u01a1ng ph\u00e1p kh\u00e1c \u0111\u1ec3 soi c\u1ea7u ph\u00e1t t\u00e0i tr\u00fang l\u1edbn.<\/p>\n

SOI C\u1ea6U MI\u1ec0N B\u1eaeC SI\u00caU CHU\u1ea8N <\/span><\/h3>\n
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